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# fspl

Free space path loss

## Syntax

L = fspl(R,lambda)

## Description

L = fspl(R,lambda) returns the free space path loss in decibels for a waveform with wavelength lambda propagated over a distance of R meters. The minimum value of L is 0, indicating no path loss.

## Input Arguments

 R Propagation distance in meters lambda Wavelength in meters. The wavelength in meters is the speed of propagation divided by the frequency in hertz.

## Output Arguments

 L Path loss in decibels. L is a nonnegative number. The minimum value of L is 0, indicating no path loss.

## Examples

Calculate free space path loss in decibels incurred by a 10 gigahertz wave over a distance of 10 kilometers.

```lambda = physconst('LightSpeed')/10e9;
R = 10e3;
L = fspl(R,lambda);```

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### Free Space Path Loss

The free-space path loss, L, in decibels is:

$L=20{\mathrm{log}}_{10}\left(\frac{4\pi R}{\lambda }\right)$

This formula assumes that the target is in the far-field of the transmitting element or array. In the near-field, the free-space path loss formula is not valid and can result in a loss smaller than 0 dB, equivalent to a signal gain. For this reason, the loss is set to 0 dB for range values R ≤ λ/4π.

## References

[1] Proakis, J. Digital Communications. New York: McGraw-Hill, 2001.