suggest me how to plot 45 degree line in MATLAB?

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how can I plot a line with 45 degree angle in the graph as reference line????
when I use the code "refline" the line I got different angle line and I want 45 degree angle line from the centre of both axes so please suggest me how can I get.
  2 个评论
Jan
Jan 2019-2-22
Please post the code, when you mention it. What is "the center of both axes"?
SAGAR PATEL
SAGAR PATEL 2019-2-23
I mean, I want 45 degree reference line. can I get that by give the same axis limit????

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采纳的回答

Jan
Jan 2019-2-22
I guess, that you do get a 45 deg angle, but that the different scaling of X and Y axes let it look in another angle. See:
axis equal
to use the same scaling for both directions.
  2 个评论
SAGAR PATEL
SAGAR PATEL 2019-2-23
so I have to give same axis limit is it right????
Stephen23
Stephen23 2019-2-23
编辑:Stephen23 2019-2-23
"so I have to give same axis limit is it right"
That depends...
To a get a 45 degree line in the data space, the axis limits are irrelevant.
If you are trying to get a 45 degree line on the screen (rather than in the data space and without using equal axis) you would need to get the displayed size of the axes and your screen resolution and figure it out the required data from that. Then the limits might be useful.

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更多回答(1 个)

Pankaj Dey
Pankaj Dey 2020-1-11
Hope this will help you.
hline = refline([1 0]);
hline.Color = 'k';
hline.LineStyle = ':';
hline.HandleVisibility = 'off';
Source: https://fanwangecon.github.io/M4Econ/graph/main/fs_lines.html
  2 个评论
John D'Errico
John D'Errico 2020-1-11
编辑:John D'Errico 2020-1-11
You still need to define the axes to have the same units. So your suggestion will fail, unless you also specify
axis equal
As proof of that fact, consider what happens if you do EXACTLY as you have suggested.
hline = refline([1 0]);
hline.Color = 'k';
hline.LineStyle = ':';
hline.HandleVisibility = 'off';
The line appears to lie at roughly a 35-40 (actually 38 degrees from a quick check) degree angle, or so. It is CLEARLY not at 45 degrees. The problem arises because MATLAB does not create a plot with equal axes. You can think of it by seeing the tick marks are a little farther apart on the screen on the x axis, per unit traveled. The result? The line does not appear to be at 45 degrees. While it really is a 45 degree line, it does not look like one.
Now however, add one more command:
axis equal
Now the line clearly lies at a 45 degree angle, and all is good in the world. Nothing has really changed from what you showed how to do, but the line is now seen to lie at 45 degrees on the screen.

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